Advertisement

Binary Tree Level Order Traversal - LeetCode 102 Solution

Binary Tree Level Order Traversal - Complete Solution Guide

Binary Tree Level Order Traversal is LeetCode problem 102, a Medium level challenge. This complete guide provides step-by-step explanations, multiple solution approaches, and optimized code in python3, java, cpp, c.

Problem Statement

Given the root of a binary tree, return the level order traversal of its nodes' values . (i.e., from left to right, level by level). Example 1: Input: root = [3,9,20,null,null,15,7] Output: [[3],[9,20],[15,7]] Example 2: Input: root = [1] Output: [[1]] Example 3: Input: root = [] Output: [] Constraints: The number of nodes in the tree is in the range [0, 2000] . -1000 <= Node.val <= 1000

Detailed Explanation

The problem asks us to perform a level order traversal of a binary tree. Level order traversal means visiting the nodes of the tree level by level, starting from the root node. For each level, we must visit the nodes from left to right. The output should be a list of lists, where each inner list represents a level of the tree and contains the values of the nodes at that level.

Solution Approach

The provided solutions use Breadth-First Search (BFS) to traverse the binary tree level by level. A queue is used to store the nodes to be visited. The algorithm iterates while the queue is not empty. In each iteration, it processes all nodes at the current level and adds their children to the queue. This ensures that nodes are visited in the correct level order.

Step-by-Step Algorithm

  1. Step 1: Initialize an empty list `result` to store the level order traversal.
  2. Step 2: If the root is null, return the empty `result` list.
  3. Step 3: Initialize a queue and add the root node to the queue.
  4. Step 4: While the queue is not empty:
  5. Step 5: Get the size of the queue, which represents the number of nodes at the current level.
  6. Step 6: Initialize an empty list `current_level` to store the values of nodes at the current level.
  7. Step 7: Iterate `level_size` times:
  8. Step 8: Dequeue a node from the queue.
  9. Step 9: Add the node's value to the `current_level` list.
  10. Step 10: Enqueue the node's left child (if it exists).
  11. Step 11: Enqueue the node's right child (if it exists).
  12. Step 12: After processing all nodes at the current level, add the `current_level` list to the `result` list.
  13. Step 13: Return the `result` list.

Key Insights

  • Insight 1: Breadth-First Search (BFS) is the most suitable algorithm for level order traversal.
  • Insight 2: A queue data structure is essential for implementing BFS efficiently.
  • Insight 3: We need to keep track of the number of nodes at each level to process each level separately.

Complexity Analysis

Time Complexity: O(n)

Space Complexity: O(n)

Topics

This problem involves: Tree, Breadth-First Search, Binary Tree.

Companies

Asked at: Adobe, Apple, Bloomberg, Gojek, Intuit, LinkedIn, Meta, Microsoft, Palo Alto Networks, PhonePe, TikTok, Uber, Yahoo.