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Airplane Seat Assignment Probability - LeetCode 1227 Solution

Airplane Seat Assignment Probability - Complete Solution Guide

Airplane Seat Assignment Probability is LeetCode problem 1227, a Medium level challenge. This complete guide provides step-by-step explanations, multiple solution approaches, and optimized code in python3, java, cpp, c.

Problem Statement

n passengers board an airplane with exactly n seats. The first passenger has lost the ticket and picks a seat randomly. But after that, the rest of the passengers will: Take their own seat if it is still available, and Pick other seats randomly when they find their seat occupied Return the probability that the n th person gets his own seat . Example 1: Input: n = 1 Output: 1.00000 Explanation: The first person can only get the first seat. Example 2: Input: n = 2 Output: 0.50000 Explanation: The

Detailed Explanation

The problem describes a scenario where 'n' passengers are boarding an airplane with 'n' seats. The first passenger loses their ticket and chooses a seat randomly. Subsequent passengers take their assigned seat if it's available; otherwise, they pick a seat at random. The goal is to determine the probability that the nth passenger gets their own assigned seat.

Solution Approach

The solution directly returns the probability based on the value of 'n'. If n is 1, the probability is 1.0 (the first passenger always gets their seat). If n is greater than 1, the probability is 0.5.

Step-by-Step Algorithm

  1. Step 1: Check if n is equal to 1.
  2. Step 2: If n is 1, return 1.0.
  3. Step 3: If n is greater than 1, return 0.5.

Key Insights

  • Insight 1: The problem is more of a probability puzzle than a complex algorithmic problem. The key is realizing the pattern that emerges after the first passenger chooses a random seat.
  • Insight 2: The crucial observation is that the nth passenger will only not get their seat if someone before them takes it. The entire seating arrangement collapses down to who takes seat 1 or seat n.
  • Insight 3: For n > 1, the probability converges to 0.5. This can be proven by induction or reasoning about possible seat choices.
  • Insight 4: The case n=1 is an edge case which needs to be handled separately. In this case, first person will definitely get his own seat with a probability of 1.

Complexity Analysis

Time Complexity: O(1)

Space Complexity: O(1)

Topics

This problem involves: Math, Dynamic Programming, Brainteaser, Probability and Statistics.

Companies

Asked at: Microstrategy, Toptal.