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Find a Value of a Mysterious Function Closest to Target - LeetCode 1521 Solution

Find a Value of a Mysterious Function Closest to Target - Complete Solution Guide

Find a Value of a Mysterious Function Closest to Target is LeetCode problem 1521, a Hard level challenge. This complete guide provides step-by-step explanations, multiple solution approaches, and optimized code in python3, java, cpp, c.

Problem Statement

Winston was given the above mysterious function func . He has an integer array arr and an integer target and he wants to find the values l and r that make the value |func(arr, l, r) - target| minimum possible. Return the minimum possible value of |func(arr, l, r) - target| . Notice that func should be called with the values l and r where 0 <= l, r < arr.length . Example 1: Input: arr = [9,12,3,7,15], target = 5 Output: 2 Explanation: Calling func with all the pairs of [l,r] = [[0,0],[1,1],[2,2],

Detailed Explanation

The problem asks us to find the minimum absolute difference between a target value and the result of a mysterious function `func(arr, l, r)`. The function `func` calculates the bitwise AND of a subarray of `arr` from index `l` to `r` (inclusive). We need to iterate through all possible subarrays of `arr`, calculate `func` for each subarray, and find the minimum absolute difference between the result and the target value. The input is an integer array `arr` and an integer `target`, and the output is the minimum possible absolute difference.

Solution Approach

The solution uses a dynamic programming approach to iteratively build a set of possible values that can be obtained by performing bitwise AND operations on subarrays ending at the current index. We maintain a set `possible` of the AND values encountered so far. For each number `num` in the array, we create a new set `new_possible` containing `num` itself. We then iterate through the `possible` set, performing a bitwise AND operation between each element `p` in `possible` and `num`, and adding the result to `new_possible`. After calculating the `new_possible` set, we iterate through it and update the minimum absolute difference `ans` with the target. The `possible` set is then updated to `new_possible` for the next iteration. This avoids recalculating overlapping subarrays.

Step-by-Step Algorithm

  1. Step 1: Initialize `ans` to infinity (or a sufficiently large value) to store the minimum absolute difference and an empty set `possible` to store the possible AND values.
  2. Step 2: Iterate through each number `num` in the input array `arr`.
  3. Step 3: Create a new set `new_possible` and add the current number `num` to it.
  4. Step 4: Iterate through the `possible` set. For each value `p` in `possible`, perform a bitwise AND operation between `p` and `num`, and add the result to `new_possible`.
  5. Step 5: Iterate through the `new_possible` set. For each value `p` in `new_possible`, calculate the absolute difference between `p` and the target, and update `ans` with the minimum value found so far.
  6. Step 6: If `ans` becomes 0, return it immediately, as it's the minimum possible difference.
  7. Step 7: Update the `possible` set to `new_possible`.
  8. Step 8: After iterating through all the numbers in `arr`, return the final value of `ans`.

Key Insights

  • Insight 1: The bitwise AND operation is monotonic decreasing as the subarray expands. This means func(arr, l, r+1) <= func(arr, l, r). This property is crucial because it allows us to track possible values from the AND operation efficiently.
  • Insight 2: Instead of computing the AND for all possible subarrays [l, r], we can iteratively build up a set of possible values at each index. For each number in the array, we can update the set of possible values by performing a bitwise AND with all the previous possible values and adding the current number to the set.
  • Insight 3: The problem's constraints on the input array's elements (1 <= arr[i] <= 10^6) is relatively small, allowing us to keep track of all possible AND values without exceeding memory limits.

Complexity Analysis

Time Complexity: O(n^2)

Space Complexity: O(n)

Topics

This problem involves: Array, Binary Search, Bit Manipulation, Segment Tree.

Companies

Asked at: American Express.