Advertisement

Most Visited Sector in a Circular Track - LeetCode 1560 Solution

Most Visited Sector in a Circular Track - Complete Solution Guide

Most Visited Sector in a Circular Track is LeetCode problem 1560, a Easy level challenge. This complete guide provides step-by-step explanations, multiple solution approaches, and optimized code in python3, java, cpp, c.

Problem Statement

Given an integer n and an integer array rounds . We have a circular track which consists of n sectors labeled from 1 to n . A marathon will be held on this track, the marathon consists of m rounds. The i th round starts at sector rounds[i - 1] and ends at sector rounds[i] . For example, round 1 starts at sector rounds[0] and ends at sector rounds[1] Return an array of the most visited sectors sorted in ascending order. Notice that you circulate the track in ascending order of sector numbers in t

Detailed Explanation

The problem simulates a marathon on a circular track with 'n' sectors. The marathon consists of 'm' rounds. Each round starts and ends at specific sectors given in the `rounds` array. The goal is to identify and return the sector(s) visited most frequently during the entire marathon, sorted in ascending order.

Solution Approach

The solution uses a frequency counting approach. It initializes a count array to store the number of times each sector is visited. Then, it iterates through the sectors visited between the start and end points of the marathon, incrementing the counter for each visited sector. Finally, it finds the maximum count and returns the sectors with that maximum count.

Step-by-Step Algorithm

  1. Step 1: Initialize a count array of size 'n' with zeros. Each index represents a sector, and the value at each index will store the count of visits to that sector.
  2. Step 2: Determine the starting sector (`start`) and ending sector (`end`) from the `rounds` array. Adjust these indices to be 0-based (subtract 1).
  3. Step 3: Handle the circular nature of the track. If `start` <= `end`, iterate from `start` to `end` (inclusive), incrementing the counts for each sector. Otherwise (if `start` > `end`), iterate from `start` to `n-1` and then from 0 to `end`, incrementing counts.
  4. Step 4: Find the maximum count among all sectors.
  5. Step 5: Iterate through the count array again. For each sector with a count equal to the maximum count, add that sector number (index + 1) to the result array.
  6. Step 6: Return the result array containing the most visited sector(s) sorted in ascending order.

Key Insights

  • Insight 1: The problem can be efficiently solved by tracking the visited sectors. Instead of simulating the entire race, we can directly determine the sectors visited between the starting sector of the first round and the ending sector of the last round.
  • Insight 2: We can use an array to count the visits to each sector. The indices of this array correspond to the sector numbers.
  • Insight 3: We need to handle the circular nature of the track. If the starting sector is greater than the ending sector, the marathon covers the end of the track and the beginning.

Complexity Analysis

Time Complexity: O(n)

Space Complexity: O(n)

Topics

This problem involves: Array, Simulation.

Companies

Asked at: Expedia.