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Sort Array by Increasing Frequency - LeetCode 1636 Solution

Sort Array by Increasing Frequency - Complete Solution Guide

Sort Array by Increasing Frequency is LeetCode problem 1636, a Easy level challenge. This complete guide provides step-by-step explanations, multiple solution approaches, and optimized code in python3, java, cpp, c.

Problem Statement

Given an array of integers nums , sort the array in increasing order based on the frequency of the values. If multiple values have the same frequency, sort them in decreasing order. Return the sorted array . Example 1: Input: nums = [1,1,2,2,2,3] Output: [3,1,1,2,2,2] Explanation: '3' has a frequency of 1, '1' has a frequency of 2, and '2' has a frequency of 3. Example 2: Input: nums = [2,3,1,3,2] Output: [1,3,3,2,2] Explanation: '2' and '3' both have a frequency of 2, so they are sorted in decr

Detailed Explanation

The problem asks you to sort an array of integers based on the frequency of each number. The sorting should prioritize numbers with lower frequency first. If two numbers have the same frequency, the number with the larger value should come first. The input is an array of integers, and the output is a new array sorted according to these rules. Constraints limit the array size and the range of integer values.

Solution Approach

The provided solutions generally follow a two-step approach: First, they count the frequency of each number using a hash map (or equivalent). Second, they sort the array based on the frequency and value using a custom comparator or a key function in the sorting algorithm. The Python solution elegantly uses a lambda function within the `sort()` method for conciseness. The Java solution employs a custom comparator for the `Collections.sort()` method, explicitly handling the frequency and value comparisons. The C++ solution uses `map` and then sorts based on frequency, followed by reverse sorting within each frequency group. The C solution uses a struct to store frequency and values, and `qsort` to sort this array.

Step-by-Step Algorithm

  1. Step 1: Count the frequency of each number using a hash map (or equivalent). For each number in the input array, increment its count in the hash map.
  2. Step 2: Sort the input array based on a custom comparison criteria. The comparison should first check the frequencies of the numbers being compared. The number with the lower frequency comes first. If frequencies are equal, the number with the higher value comes first.
  3. Step 3: Return the sorted array.

Key Insights

  • Insight 1: Using a hash map (or dictionary in Python) to efficiently count the frequency of each number is crucial for achieving an optimal time complexity.
  • Insight 2: The sorting process requires a custom comparison function (or lambda in Python) that prioritizes frequency first (ascending) and then value (descending) when frequencies are equal.
  • Insight 3: Handling negative numbers correctly is important, as the example includes negative integers. The sorting criteria must work correctly regardless of sign.

Complexity Analysis

Time Complexity: O(nlogn)

Space Complexity: O(n)

Topics

This problem involves: Array, Hash Table, Sorting.

Companies

Asked at: Accenture, Agoda, Akuna Capital, SAP, tcs.