Advertisement

Equal Row and Column Pairs - LeetCode 2352 Solution

Equal Row and Column Pairs - Complete Solution Guide

Equal Row and Column Pairs is LeetCode problem 2352, a Medium level challenge. This complete guide provides step-by-step explanations, multiple solution approaches, and optimized code in python3, java, cpp, c.

Problem Statement

Given a 0-indexed n x n integer matrix grid , return the number of pairs (r i , c j ) such that row r i and column c j are equal . A row and column pair is considered equal if they contain the same elements in the same order (i.e., an equal array). Example 1: Input: grid = [[3,2,1],[1,7,6],[2,7,7]] Output: 1 Explanation: There is 1 equal row and column pair: - (Row 2, Column 1): [2,7,7] Example 2: Input: grid = [[3,1,2,2],[1,4,4,5],[2,4,2,2],[2,4,2,2]] Output: 3 Explanation: There are 3 equal ro

Detailed Explanation

The problem asks us to count the number of pairs (row_i, col_j) in a given n x n integer matrix 'grid' where the row row_i and the column col_j are identical as arrays. In simpler terms, we need to find how many times a row is exactly the same as a column in the grid. The input is a 2D integer array representing the grid. The output is a single integer representing the count of such row-column pairs. The constraints specify the size of the grid (1 <= n <= 200) and the range of values in the grid (1 <= grid[i][j] <= 10^5).

Solution Approach

The solution uses a hash table to count the occurrences of each row in the grid. Then, it iterates through each column of the grid, creates a tuple (or string representation) of the column, and checks if this column exists as a row in the hash table. If it does, the count is incremented by the number of times that row exists. This approach avoids redundant comparisons and efficiently finds the matching row-column pairs.

Step-by-Step Algorithm

  1. Step 1: Create a hash table (Counter in Python, HashMap in Java, map in C++) to store the count of each row in the grid.
  2. Step 2: Iterate through each row of the grid.
  3. Step 3: Convert the row into a string or tuple format so it can be used as a key in the hash table.
  4. Step 4: Update the count of the row in the hash table.
  5. Step 5: Iterate through each column of the grid.
  6. Step 6: Create a temporary array (or list) to store the values of the current column.
  7. Step 7: Convert the column into a string or tuple format so it can be compared with row keys in the hash table.
  8. Step 8: Look up the column in the hash table to find how many times it appears as a row.
  9. Step 9: Add the count to the total number of equal row and column pairs.
  10. Step 10: Return the total count.

Key Insights

  • Insight 1: The core idea is to efficiently compare each row with every column and count the matches. Direct comparison in a naive nested loop approach will work, but it can be optimized.
  • Insight 2: Using a hash table (or dictionary) to store the counts of each row can significantly improve the efficiency of finding matching columns. We can then iterate through the columns and check how many times each column appears as a row.
  • Insight 3: Converting the rows and columns to a string or tuple representation allows us to use them as keys in the hash table, since arrays themselves are not hashable in some languages.

Complexity Analysis

Time Complexity: O(n^2)

Space Complexity: O(n^2)

Topics

This problem involves: Array, Hash Table, Matrix, Simulation.

Companies

Asked at: DE Shaw.