Maximal Score After Applying K Operations - Complete Solution Guide
Maximal Score After Applying K Operations is LeetCode problem 2530, a Medium level challenge. This complete guide provides step-by-step explanations, multiple solution approaches, and optimized code in python3, java, cpp, c.
Problem Statement
You are given a 0-indexed integer array nums and an integer k . You have a starting score of 0 . In one operation : choose an index i such that 0 <= i < nums.length , increase your score by nums[i] , and replace nums[i] with ceil(nums[i] / 3) . Return the maximum possible score you can attain after applying exactly k operations . The ceiling function ceil(val) is the least integer greater than or equal to val . Example 1: Input: nums = [10,10,10,10,10], k = 5 Output: 50 Explanation: Apply the op
Detailed Explanation
The problem asks us to find the maximum possible score achievable after applying exactly `k` operations on a given array `nums`. In each operation, we select an index `i` from `nums`, increase our score by the value at that index (`nums[i]`), and then replace `nums[i]` with the ceiling of `nums[i] / 3`. The goal is to maximize the total score after `k` operations.
Solution Approach
The solution uses a greedy approach combined with a max-heap data structure. We initialize a max-heap with the elements of the input array `nums`. Then, we iterate `k` times, each time extracting the maximum element from the heap, adding it to the score, calculating the new value (ceiling of val/3), and inserting the new value back into the heap. This ensures that we always pick the largest available number in each operation, maximizing our score.
Step-by-Step Algorithm
- Step 1: Initialize a max-heap with all elements from the `nums` array.
- Step 2: Initialize a score variable to 0.
- Step 3: Iterate `k` times:
- Step 4: In each iteration, extract the maximum element (`val`) from the max-heap.
- Step 5: Add `val` to the `score`.
- Step 6: Calculate the new value `new_val` as the ceiling of `val / 3`. This can be done as `(val + 2) / 3` in integer arithmetic.
- Step 7: Insert `new_val` into the max-heap.
- Step 8: After `k` iterations, return the final `score`.
Key Insights
- Insight 1: The greedy approach of always picking the largest number available at each step is optimal because we want to maximize our score as quickly as possible.
- Insight 2: A max-heap data structure is perfectly suited for efficiently tracking the largest number at each step and updating it after each operation.
- Insight 3: The `ceil(nums[i] / 3)` operation needs careful handling to ensure correctness across different programming languages. For example, integer division can truncate, so adding 2 before dividing by 3 can correctly emulate the `ceil` function for positive integers.
Complexity Analysis
Time Complexity: O(n + k log n)
Space Complexity: O(n)
Topics
This problem involves: Array, Greedy, Heap (Priority Queue).
Companies
Asked at: McKinsey.