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Pass the Pillow - LeetCode 2582 Solution

Pass the Pillow - Complete Solution Guide

Pass the Pillow is LeetCode problem 2582, a Easy level challenge. This complete guide provides step-by-step explanations, multiple solution approaches, and optimized code in python3, java, cpp, c.

Problem Statement

There are n people standing in a line labeled from 1 to n . The first person in the line is holding a pillow initially. Every second, the person holding the pillow passes it to the next person standing in the line. Once the pillow reaches the end of the line, the direction changes, and people continue passing the pillow in the opposite direction. For example, once the pillow reaches the n th person they pass it to the n - 1 th person, then to the n - 2 th person and so on. Given the two positive

Detailed Explanation

The problem simulates passing a pillow among `n` people standing in a line. Initially, person 1 holds the pillow. Every second, the pillow is passed to the next person. When the pillow reaches either end of the line, the direction reverses. The goal is to find the index of the person holding the pillow after a given `time` (in seconds).

Solution Approach

The Python and C solutions use a simulation approach, iteratively moving the pillow according to the rules. The Java and C++ solutions leverage mathematical insight to efficiently calculate the final position without explicit simulation. They identify the length of a complete cycle and use the modulo operator to find the position after a certain number of cycles.

Step-by-Step Algorithm

  1. Step 1: (Simulation Approach) Initialize the person holding the pillow to 1 and the direction of passing to 1 (forward).
  2. Step 2: (Simulation Approach) Iterate `time` times, updating the person's index and reversing the direction when the pillow reaches the line's ends.
  3. Step 3: (Simulation Approach) Return the final index of the person holding the pillow.
  4. Step 1: (Mathematical Approach) Check if `time` is less than or equal to `n`. If so, the pillow is still within the initial forward pass, and the result is simply `time`.
  5. Step 2: (Mathematical Approach) Calculate the length of a full cycle (forward and backward pass): `2 * (n - 1)`.
  6. Step 3: (Mathematical Approach) Calculate the remaining time after completing full cycles: `time % cycle_length`.
  7. Step 4: (Mathematical Approach) Determine the person's index based on the remaining time: If it's within the forward pass, the index is `n - rem`; otherwise (backward pass), it's `rem - (n - 1) + 1`.

Key Insights

  • Insight 1: Recognizing the cyclical nature of the pillow passing. After the pillow reaches the end of the line and changes direction, the pattern repeats.
  • Insight 2: Understanding that the efficient solution involves calculating the remainder after accounting for full cycles of passing the pillow.
  • Insight 3: Handling edge cases where `time` is less than or equal to `n` (meaning the pillow hasn't changed direction yet).

Complexity Analysis

Time Complexity: O(t)

Space Complexity: O(1)

Topics

This problem involves: Math, Simulation.

Companies

Asked at: MathWorks.