Advertisement

Chalkboard XOR Game - LeetCode 810 Solution

Chalkboard XOR Game - Complete Solution Guide

Chalkboard XOR Game is LeetCode problem 810, a Hard level challenge. This complete guide provides step-by-step explanations, multiple solution approaches, and optimized code in python3, java, cpp, c.

Problem Statement

You are given an array of integers nums represents the numbers written on a chalkboard. Alice and Bob take turns erasing exactly one number from the chalkboard, with Alice starting first. If erasing a number causes the bitwise XOR of all the elements of the chalkboard to become 0 , then that player loses. The bitwise XOR of one element is that element itself, and the bitwise XOR of no elements is 0 . Also, if any player starts their turn with the bitwise XOR of all the elements of the chalkboard

Detailed Explanation

The Chalkboard XOR Game challenges us to determine if Alice, playing optimally, can win a game involving erasing numbers from a chalkboard. The rules are: players take turns erasing one number at a time. If a player's erasure causes the bitwise XOR of the remaining numbers to become 0, they lose. If a player starts their turn with the XOR already being 0, they win. We need to return 'true' if Alice wins, assuming both players play perfectly. Input is an array 'nums' of integers. Output is a boolean representing if Alice wins.

Solution Approach

The solution leverages the game theory aspect. If the initial XOR sum is zero, Alice wins immediately. Otherwise, Alice wins if and only if the number of elements in the array is even. This stems from the fact that if the array length is even and the XOR sum is non-zero, Alice can always make a move that leaves the XOR sum non-zero for Bob, and since the array length is even, Bob will eventually be left with a single number (XOR sum equals the number itself) which is not zero, and then Alice wins.

Step-by-Step Algorithm

  1. Step 1: Calculate the XOR sum of all elements in the 'nums' array.
  2. Step 2: Check if the XOR sum is equal to 0. If it is, return 'true' (Alice wins).
  3. Step 3: If the XOR sum is not 0, check if the length of the 'nums' array is even.
  4. Step 4: If the length is even, return 'true' (Alice wins). Otherwise, return 'false' (Alice loses).

Key Insights

  • Insight 1: If the initial XOR sum of all numbers is 0, Alice wins immediately.
  • Insight 2: If the length of the array is even, Alice can always win. This can be proven using game theory.
  • Insight 3: If the XOR sum is not zero and the length of the array is odd, Bob can always force a win for himself.

Complexity Analysis

Time Complexity: O(n)

Space Complexity: O(1)

Topics

This problem involves: Array, Math, Bit Manipulation, Brainteaser, Game Theory.

Companies

Asked at: HashedIn.