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Validate Stack Sequences - LeetCode 946 Solution

Validate Stack Sequences - Complete Solution Guide

Validate Stack Sequences is LeetCode problem 946, a Medium level challenge. This complete guide provides step-by-step explanations, multiple solution approaches, and optimized code in python3, java, cpp, c.

Problem Statement

Given two integer arrays pushed and popped each with distinct values, return true if this could have been the result of a sequence of push and pop operations on an initially empty stack, or false otherwise. Example 1: Input: pushed = [1,2,3,4,5], popped = [4,5,3,2,1] Output: true Explanation: We might do the following sequence: push(1), push(2), push(3), push(4), pop() -> 4, push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1 Example 2: Input: pushed = [1,2,3,4,5], popped = [4,3,5,1,2] Outpu

Detailed Explanation

The problem asks us to determine whether a given `popped` array could have been the result of a sequence of push and pop operations on an initially empty stack, given an array `pushed` representing the sequence of elements being pushed onto the stack. Both arrays contain distinct values, `popped` is a permutation of `pushed`, and we must simulate stack operations to validate the `popped` sequence. The arrays represent push and pop operations on a stack, and the goal is to confirm if the `popped` array represents a valid pop sequence after pushing the elements from the `pushed` array.

Solution Approach

The provided solutions use a stack to simulate the push and pop operations. It iterates through the `pushed` array, pushing each element onto the stack. After each push, it checks if the top element of the stack matches the next element in the `popped` array. If they match, it pops the element from the stack and increments the `popped` array's index. This process continues until either the stack is empty or the top element doesn't match the next element in the `popped` array. After processing all the elements from `pushed`, if the stack is empty, it means all elements were popped in the correct sequence, and the function returns true. Otherwise, it returns false.

Step-by-Step Algorithm

  1. Step 1: Initialize an empty stack to simulate the stack operations and a `pop_index` to 0 to track the current position in the `popped` array.
  2. Step 2: Iterate through the `pushed` array. For each element in `pushed`, push it onto the stack.
  3. Step 3: After each push operation, enter a `while` loop that continues as long as the stack is not empty, the `pop_index` is within the bounds of the `popped` array, and the top element of the stack matches the element at `popped[pop_index]`.
  4. Step 4: Inside the `while` loop, pop the top element from the stack and increment the `pop_index` to move to the next element in the `popped` array.
  5. Step 5: After the loop finishes, check if the stack is empty. If it's empty, it means all elements have been successfully pushed and popped according to the given sequences, so return `true`. Otherwise, return `false`.

Key Insights

  • Insight 1: The core idea is to simulate the push and pop operations using a stack data structure. The pushed array provides the order of insertions, and the popped array determines the expected order of removals.
  • Insight 2: Maintaining a pointer (index) to the popped array helps track the expected order of pops. We continuously push elements from the pushed array onto the stack and then attempt to pop elements from the stack if they match the expected popped order.
  • Insight 3: If, after processing all the push operations, the stack is empty, then the popped array represents a valid sequence; otherwise, it does not.

Complexity Analysis

Time Complexity: O(n)

Space Complexity: O(n)

Topics

This problem involves: Array, Stack, Simulation.

Companies

Asked at: Apollo.io.